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Question

The following table, reproduced from earlier exercise, gives the probability distribution of the number of patients who enter Millard Fellmore Memorial Hospital's emergency room in a given hour.

 Patients per hour 0123456 Probability .2725.3543.2303.0998.0324.0084.0023\begin{array}{l|ccccccc} \hline \text { Patients per hour } & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text { Probability } & .2725 & .3543 & .2303 & .0998 & .0324 & .0084 & .0023 \\ \hline \end{array}

Calculate this probability distribution's mean and standard deviation.

Solution

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Answered 1 year ago
Answered 1 year ago
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Recall the formulas for the mean, μ\mu, and the standard deviation, σ\sigma:

μ=xP(x)σ=x2P(x)μ2\begin{aligned} \mu&=\sum xP(x)\\ \sigma&=\sqrt{\sum x^2P(x)-\mu^2} \end{aligned}

For this problem, xx refers to the number of patients entering the emergency room during a 11-hour period at Millard Fellmore Memorial Hospital

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