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Question

The frequency distribution shows the number of medical tests conducted on 30 randomly selected emergency room patients.

Number of tests performed Number of patients
0 11
1 9
2 5
3 4
4 or more 1

If a patient is selected at random, find these probabilities:

a. The patient had exactly 3 tests done. b. The patient had at most 2 tests done. c. The patient has 1 or 2 tests done. d. The patient had fewer than 3 tests done. e. The patient had at least 3 tests done.

Solution

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Answered 2 years ago
Answered 2 years ago
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The data given to us is for the number of items sold by a sales representative who visits customers at home.

From the data we can calculate following :

total number of home=8+10+3+2+1=24\text{total number of home} = 8+10+3+2+1 = 24

(a) \text{\textcolor{#4257b2}{\textbf{(a) }}} Using the formula of empirical probability, we can write the probability that exactly 1 item was sold as:

P(exactly 1 item)=(number of times she sold 1 itemtotal number of homes)=(1024)P(exactly 1 item)=512\begin{align*} \text{P(exactly 1 item)} &= \left(\dfrac{\text{number of times she sold 1 item}}{\text{total number of homes}}\right)\\ &= \left(\dfrac{10}{24}\right)\\ \text{P(exactly 1 item)} &= \dfrac{5}{12} \end{align*}

Formula for empirical probability : \textbf{Formula for empirical probability : } Given a frequency distribution, the probability of an event being in a given class is :

P(E)=frequency for the classtotal frequencies in the distribution=fnP(E) = \dfrac{\text{frequency for the class}}{\text{total frequencies in the distribution}} = \dfrac{f}{n}

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