## Related questions with answers

Question

The function given by $f(x)=k 2^{x / 12}$ can be used to determine the frequency, in cycles per second, of a musical note that is $x$ half-steps above a note with frequency $k^*.$

Show that the $\mathrm{C}$ sharp that is $4$ half-steps (a "major third") above concert A (see the previous exercise) has a frequency that is about $25 \%$ greater than that of concert $\mathrm{A}$.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 3Based on the problem, we let:

$\begin{aligned} k&=440 \text{ cycles per second}\\ x&=4 \text{ half-steps}\\ \end{aligned}$

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