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Question

# The general form of a nonvertical line in slope-intercept form is y = mx + b. What is the general form of a line perpendicular to y = mx + b, in slope-intercept form?

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The equation $y=mx+b$ tells us that the slope is m, where the slope of the equation is the number standing next to $x$.

To find the general form of a line perpendicular to $y=mx+b$ we will use the condition that the perpendicular line has a negative reciprocal of the given equation.

Since the slope of the equaition $y=mx+b$ is $m$ the slope of perpendicular line is $\boxed{-\dfrac{1}{m}}$.

In slope-intercept form of perpendicular line is:

$\boxed{y=-\dfrac{1}{m}x+b }$

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