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The general form of a nonvertical line in slope-intercept form is y = mx + b. What is the general form of a line perpendicular to y = mx + b, in slope-intercept form?

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The equation y=mx+by=mx+b tells us that the slope is m, where the slope of the equation is the number standing next to xx.

To find the general form of a line perpendicular to y=mx+by=mx+b we will use the condition that the perpendicular line has a negative reciprocal of the given equation.

Since the slope of the equaition y=mx+by=mx+b is mm the slope of perpendicular line is 1m\boxed{-\dfrac{1}{m}}.

In slope-intercept form of perpendicular line is:

y=1mx+b\boxed{y=-\dfrac{1}{m}x+b }

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