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The genotype of F1 individuals in a tetrahybrid cross is AaBbCcDd. Assuming independent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes?
(a) aabbccdd
(b) AaBbCcDd
(c) AABBCCDD
(d) AaBBccDd
(e) AaBBCCdd
Solution
VerifiedThe genotype of F1 individuals is $\textbf{\color{#c34632}AaBbCcDd}$.
$\textbf{\underline{So The probabilities of F2 offspring are the following}}$:

$\textbf{\color{#4257b2}(aabbccdd)}$ = $1/4 \times 1/4 \times 1/4 \times 1/4$ = \textbf$\color{#c34632}1/256$.

$\textbf{\color{#4257b2}(AaBbCcDd)}$ = $1/2 \times 1/2 \times 1/2 \times 1/2$ = \textbf$\color{#c34632}1/16$.

$\textbf{\color{#4257b2}(AABBCCDD)}$ = $1/4 \times 1/4 \times 1/4 \times 1/4$ = \textbf$\color{#c34632}1/256$ .

$\textbf{\color{#4257b2}(AaBBccDd)}$ = $1/2 \times 1/4 \times 1/4 \times 1/2$ = \textbf$\color{#c34632}1/64$.

$\textbf{\color{#4257b2}(AaBBCCdd)}$ = $1/2 \times 1/4 \times 1/4 \times 1/4$ = \textbf$\color{#c34632}1/128$.
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