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Question

The given set is a subset of C[−1, 1]. Which of these are also vector spaces? F={f(x)F=\{f(x) in C[1,1]:f(1)=0}C[1,1]: f(1)=0\}

Solution

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Because the set is subspace of a vector space C[1,1]C[-1,1], we only need to show (c1),(c2),(a3),(a4)(c1), (c2), (a3), (a4).

Choose any f,gFf,g\in F and any scalar aa.

(c1)(c1) (f+g)(1)=f(1)+g(1)=0+0=0(f+g)(1)=f(1)+g(1)=0+0=0. Conclude that f+gFf+g \in F.

(c2)(c2) (af)(1)=af(1)=a0=0(af)(1)=af(1)=a0=0. Conclude that afFaf \in F.

(a3)(a3) Define θ=0\theta=0 where 00 is nul-function. 0(1)=00(1)=0 so 0F0 \in F. Also (f+0)(t)=f(t)+0(t)=f(t)(f+0)(t)=f(t)+0(t)=f(t).

(a4)(a4) For given fFf \in F define f-f as in C[1,1]C[-1,1], (f)(t)=f(t)(-f)(t)=-f(t). (f)(1)=f(1)=0=0(-f)(1)=-f(1)=-0=0 so fF-f \in F. (f+(f))(t)=f(t)+(f)(t)=f(t)f(t)=0(f+(-f))(t)=f(t)+(-f)(t)=f(t)-f(t)=0.

Conclude that FF is a vector space.

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