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The gold foil that Rutherford used in his scattering experiment had a thickness of approximately 0.005 mm. If a single gold atom has a diameter of 2.9 X 10 10^{-10} m, how many atoms thick was Rutherford’s foil?

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In this problem, we are asked to determine how many atoms thick was Rutherford's foil that he used in his experiment given its approximate thickness. The diameter of a single gold atom is also given. To solve this problem, we must first apply the correct conversion factor such that all units are the same. Then, use the calculated values and set up the appropriate equations so that the undesired units cancel.

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