Question

The gross annual earnings of a certain company were A(t)=0.1t2+10t+20A(t)=0.1 t^2+10 t+20 thousand dollars tt years after its formation in 2004.

a. At what rate were the gross annual earnings of the company growing with respect to time in 2008 ?

b. At what percentage rate were the gross annual earnings growing with respect to time in 2008?

Solution

Verified
Answered 1 year ago
Answered 1 year ago
Step 1
1 of 2

The given function is A(t)=0.1t2+10t+20A(t)=0.1t^2+10t+20 Hence the derivative is

dAdt=0.2t+10\begin{align} \frac{dA}{dt}&=0.2t+10 \end{align}

In the year 2004, the rate of change is

dAdtt=4=10.8\begin{align} \frac{dA}{dt}\bigg|_{t=4}&=10.8 \end{align}

i.e., 10,800 dollar per year.

Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Continue with GoogleContinue with Facebook

Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Continue with GoogleContinue with Facebook