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Question

The height h in feet of a car on a different Ferris wheel can be modeled by h(t)=16cosπ45t+24h(t)=-16 \cos \frac{\pi}{45} t+24, where t is the time in seconds. Determine the period, midline, amplitude, and maximum and minimum values of the graph. For one cycle starting from t=0, identify all points where the graph intersects its midline and the coordinates of any local maxima and minima. Interpret these points in the context of the problem, and graph one cycle.

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Answered 2 years ago
Answered 2 years ago
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We see that 1b=π45\frac{1}{b}=\frac{\pi}{45}, so b=45πb=\frac{45}{\pi}. Therefore, the period is:

2πb=2π45π=90\begin{aligned} 2\pi\cdot b&=2\pi\cdot \frac{45}{\pi}\\ &=90 \end{aligned}

Midline is y=ky=k or y=24y=24. Amplitude is a=16a=16. Maximum value:

k+a=24+16=40\begin{aligned} k+a&=24+16\\ &=40 \end{aligned}

Minimum value:

ka=2416=8\begin{aligned} k-a&=24-16\\ &=8 \end{aligned}

When t=0t=0,

h(t)=16cos(π450)+24=161+24=8\begin{aligned} h(t)&=-16\cos\left(\frac{\pi}{45}\cdot 0\right)+24\\ &=-16\cdot 1+24\\ &=8 \end{aligned}

So, point (0,8)(0, 8) is on the graph. Also, this is a minimum. There is a second minimum and he is at the end of the cycle at (0+90,8)=(90,8)(0+90, 8)=(90, 8).

A maximum lies halfway between the xx-values of the minima at 0+902=45\frac{0+90}{2}=45. So, point (45,40)(45, 40) is on the graph.

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