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The height of a projectile is given by s(t)=64t2+192ts(t)=-64 t^2+192 t Find the average rate of change of the height from t=1t=1 second to t=1.5t=1.5 seconds.


Answered 2 years ago
Answered 2 years ago
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To find the average rate on the interval [a,b][a, b] We use the formula:

Average rate=f(b)f(a)ba(1)\begin{aligned} \text{Average rate}=\dfrac{f(b)-f(a)}{b-a}&&&(1) \end{aligned}

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