The heights (in inches) of men have a distribution that is approximately normal, so it appears that those heights are from a normally di tributed population. Are the logarithms of normally distributed heights also normally distributed?

The distribution of heights of adult American men is approximately Normal with mean 69 inches and standard deviation 2.5 inches. Use the 68-95-99-7 rule to answer the question. What percent of men are taller than 74 inches?

Suppose that in a certain population, individuals’ heights are approximately normally distributed with parameters $\mu=70$ and $\sigma=3$ in. a. What proportion of the population is over 6 ft. tall? b. What is the distribution of heights if they are expressed in centimeters? In meters?

The distribution of heights of adult American men is approximately normal, with mean $\mu=69$ inches and standard deviation $\sigma=2.5$ inches. Sketch this probability distribution. Label the mean and the points that are 1, 2, and 3 standard deviations from the mean.

The distribution of heights of adult American men is approximately Normal with mean 69 inches and standard deviation 2.5 inches. Draw a Normal curve on which this mean and standard deviation are correctly located.

The height of an 18 year old boy is normally distributed with mean 187 cm. Fifteen percent of 18 year old boys have heights greater than 193 cm. Find the probability that two 18 year old boys, chosen at random, will have heights greater than 185 cm.

In a statistics class survey, students reported their heights in inches. The instructor entered the data into a computer file and used statistical software to find separate five number summaries for men and women in the class. In the five-number summary for men, the minimum height was 17 inches, an obvious outlier. What is a possible reason for this outlier, and what should the instructor do about it?

The distribution of heights of adult American men is approximately Normal with mean 69 inches and standard deviation 2.5 inches. Use the 68-95-99.7 rule to answer the question. A height of 71.5 inches corresponds to what percentile of adult male American heights?

The heights of 18 year old boys are normally distributed with a mean of 187 cm. Fifteen percent of all these boys have heights greater than 193 cm. Find the probability that two 18 year old boys chosen at random will have heights greater than 185 cm.

Suppose the heights (in inches) of adult males in the United States are normally distributed with a mean of 72 inches and a standard deviation of 2 inches. Find the percent of men who are no more than 68 inches tall.

The distribution of the heights of young women aged 18 to 24 is approximately Normal with mean 65 inches and standard deviation 2.5 inches. Sketch a picture of a Normal curve and then use the 68-95-99.7 rule to show what the rule states about these women's heights.

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with a mean of 0 and a standard deviation of 1.

z=-0.84

z=1.28

Assume that men’s heights have a distribution that is symmetric and unimodal, with a mean of 69 inches and a standard deviation of 3 inches.

a. What men’s height corresponds to a z-score of 2.00?

b. What men’s height corresponds to a z-score of -1.50?

The distribution of heights of adult American men is approximately normal with a mean of 69 inches and a standard deviation of 2.5 inches. What percent of men are between 5 feet ( 60 inches) and 6 feet tall?