Question

The human body has a surface area of approximately 1.8m21.8 \mathrm{m}^{2}, a surface temperature of approximately 30C30^{\circ} \mathrm{C}, and a typical emissivity at infrared wavelengths of e = 0.97. If we make the approximation that all photons are emitted at the wavelength of peak intensity, how many photons per second does the body emit?

Solution

Verified
Answered 1 year ago
Answered 1 year ago
Step 1
1 of 2

To get the number of photons emitted by a human body per second we need two variables, energy of a single photon and energy emitted in one second. First we get the latter by employing Stefan-Boltzman's law, Q=eσAT4ΔtQ=e\sigma A T^4 \Delta t so we can write Q=0.97×5.67×108×1.8×(303.15)4Q=0.97\times 5.67 \times 10^{-8} \times 1.8 \times (303.15)^4 Q=836JQ=836 \textrm{J} Now, we can get the λpeak\lambda_{peak} λpeak=2.9×103303.15\lambda_{peak}=\frac{2.9 \times 10^{-3}}{303.15} λpeak=9570nm\lambda_{peak}=9570 \textrm{nm} From here the energy of single photon is Eph=hcλpeakE_{ph}=\frac{hc}{\lambda_{peak}} Eph=6.63×1034×3×1089570×109E_{ph}=\frac{6.63\times 10^{-34}\times 3\times 10^8}{9570 \times 10^{-9}} Eph=2×1020J.E_{ph}=2\times 10^{-20} \textrm{J}. Finally, the number of photons is N=QEphN=\frac{Q}{E_{ph}} N=417×1020N=417\times 10^{20}

Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Continue with GoogleContinue with Facebook

Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Continue with GoogleContinue with Facebook

More related questions

1/4

1/7