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The isotope cobalt 60 has a decay constant r=4.2×r=4.2 \times 101 s110^{-1} \mathrm{~s}^{-1}. Consider a pure sample of 1μg1 \mu \mathrm{g} of 60Co{ }^{60} \mathrm{Co}. (a) How many atoms are in this sample? (b) How many 60Co{ }^{60} \mathrm{Co} atoms will remain after one year? (c) What is the half-life of 60Co{ }^{60} \mathrm{Co} ?

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Cobalt 60 is considered radioactive. It has a decay constant r=4.2×109 s1r=4.2\times10^{-9}\text{ s}^{-1}. Theredore, a 1 μg1\text{ }\mu \text{g} of 60Co^{60}\text{Co} will decrease exponentially over time.

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