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Question

The isotope cobalt 60 has a decay constant $r=4.2 \times$ $10^{-1} \mathrm{~s}^{-1}$. Consider a pure sample of $1 \mu \mathrm{g}$ of ${ }^{60} \mathrm{Co}$. (a) How many atoms are in this sample? (b) How many ${ }^{60} \mathrm{Co}$ atoms will remain after one year? (c) What is the half-life of ${ }^{60} \mathrm{Co}$ ?

Solution

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Answered 2 years ago

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1 of 6Cobalt 60 is considered radioactive. It has a decay constant $r=4.2\times10^{-9}\text{ s}^{-1}$. Theredore, a $1\text{ }\mu \text{g}$ of $^{60}\text{Co}$ will decrease exponentially over time.

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