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The KspK_{s p} of SrSO4\mathrm{SrSO}_4 is 7.6×1077.6 \times 10^{-7}. Should precipitation occur when 25.0 mL25.0 \mathrm{~mL} of 1.0×103MSrCl21.0 \times 10^{-3} \mathrm{M} \mathrm{SrCl}_2 solution are mixed with 15.0 mL15.0 \mathrm{~mL} of 2.0×103 M Na2SO42.0 \times 10^{-3}~M\mathrm{~Na}_2 \mathrm{SO}_4 ? Show proof.

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Answered 2 years ago
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In this task, we need to determine if precipitate SrSO4_4 will form.

The precipitate will form when the the product of the molar concentration of the ions in solution ( raised to the potency of its stoichiometric factor) is greater than the KspK_{sp}. If the product is less than the KspK_{sp}, the precipitate will not occur.

From the dissociation reaction, we determine the mole ratio of ion and solution.

We use the molarity and volume of the solution to determine how many moles of ion we have:

n=cVn=c \cdot V

Then we calculate total volume of solution that is the sum of volume of two solution. Then, we calculate concentration of each ion using the moles and total volume:

c=nVc=\dfrac{n}{V}

Then we write the reaction quotient (QspQ_{sp}) using the initial concentration of ions. If the QspQ_{sp}>KspK_{sp}, the precipitate will occur.

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