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The long, straight wire shown in Fig. we saw earlier carries constant current ll. A metal bar with length LL is moving at constant velocity v\overrightarrow{\boldsymbol{v}}, as shown in the figure. Point aa is a distance dd from the wire. If the bar is replaced by a rectangular wire loop of resistance RR, what is the magnitude of the current induced in the loop?

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Answered 1 year ago
Answered 1 year ago

c)

'slader'

Now if we replace the bar with a loop with a width of WW and length of LL as shown in the following figure. The induced emf in the loop is,

E=dΦBdt\mathcal{E}=-\frac{d\Phi_{B}}{dt}

where ΦB=BA\Phi_{B}=BA. As we move parallel to the wire, the magnetic field is constant, so,

dΦBdt=0\frac{d\Phi_{B}}{dt}=0

hence,

E=0\mathcal{E}=0

therefore,

I=0\boxed{I=0}

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