## Related questions with answers

The magnetic field of a "shunt-wound" dc motor is produced by field coils placed in parallel to the armature coils. Suppose that the field coils have a resistance of $66.0 ~\Omega$ and the armature coils $5.00 ~\Omega$. The back emf at full speed is $105 ~\mathrm{V}$ when the motor is connected to a $115$-$\mathrm{V}$ line. (a) Draw the equivalent circuit for the situations when the motor is just starting and when it is running full speed. (b) What is the total current drawn by the motor at start up? (c) What is the total current drawn when the motor runs at full speed?

Solution

Verified**Given information:**

$\begin{aligned} R_{field} &= 66.0 \ \Omega \\ R_{armature}&= 5.00 \ \Omega \\ \mathcal{E}_{back}&= 105 \ \text{V} \\ \mathcal{E} &= 115 \ \text{V} \\ \end{aligned}$

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