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The mass of a radioactive isotope at time t (in years) is M(t)=200e0.14tgM(t)=200 e^{-0.14 t} \mathrm{g}. What is the mass of the isotope initially? How fast is the mass of the isotope changing 2 years later?

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To find the initial mass of the isotope we will compute M(0)M(0).

M(0)=200e0.140=200\pmb{M(0)}=200\cdot e^{-0.14\cdot 0}=\pmb{200}

We conclude that the initial mass of the isotope is 200g200\mathrm{\,\,g}.

To find how fast the mass of the isotope is changing after 22 years we will compute M(2)M^\prime(2).

M(t)=(200e0.14t)=200e0.14t(0.14t)=2000.14e0.14t=28e0.14t\begin{align*} M^\prime(t)&=(200\cdot e^{-0.14t})^\prime\\ &=200\cdot e^{-0.14t}\cdot (-0.14t)^\prime\\ &=-200\cdot 0.14\cdot e^{-0.14t}\\ &=28\cdot e^{-0.14t} \end{align*}

Substituting t=2t=2 in M(t)M^\prime(t) we get

M(2)=21.16\boxed{M^\prime(2)=-21.16}

We conclude that the mass of the isotope is changing approximately 21g-21\mathrm{\,\, g} per year.

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