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Question

The mass of the helicopter is 9300 kg9300 \mathrm{~kg}. It takes off vertically at time t=0t=0. The pilot advances the throttle so that the upward thrust of its engine (in kN\mathrm{kN} ) is given as a function of time in seconds by T=100+2t2T=100+2 t^2. (a) Determine the magnitude of the linear impulse due to the forces acting on the helicopter from t=0t=0 to t=3 st=3 \mathrm{~s}. (b) Use the principle of impulse and momentum to determine how fast the helicopter is moving at t=3 st=3 \mathrm{~s}.

Solution

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Answered 1 year ago
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a) There are 2 main forces applied on the helicopter: the thrust of the engine (TT) and the weight of the helicopter (WW). Thus, the resultant force (FF) applied on the helicopter can be found as following:

F=TW\begin{aligned} F&=T-W\\ \end{aligned}

In the calculation process, we have to divide the value of WW by 1000 as the value of TT is given in kN\text{kN}.

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