## Related questions with answers

The mass of the helicopter is $9300 \mathrm{~kg}$. It takes off vertically at time $t=0$. The pilot advances the throttle so that the upward thrust of its engine (in $\mathrm{kN}$ ) is given as a function of time in seconds by $T=100+2 t^2$. (a) Determine the magnitude of the linear impulse due to the forces acting on the helicopter from $t=0$ to $t=3 \mathrm{~s}$. (b) Use the principle of impulse and momentum to determine how fast the helicopter is moving at $t=3 \mathrm{~s}$.

Solution

Verifieda) There are 2 main forces applied on the helicopter: the thrust of the engine ($T$) and the weight of the helicopter ($W$). **Thus, the resultant force ($F$) applied on the helicopter can be found as following:**

$\begin{aligned} F&=T-W\\ \end{aligned}$

In the calculation process, we have to divide the value of $W$ by 1000 as the value of $T$ is given in $\text{kN}$.

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