Question

The mineral magnetite is an iron oxide ore that has a density of 5.20 g/cm35.20 \mathrm{~g} / \mathrm{cm}^3. At high temperature, magnetite reacts with carbon monoxide to yield iron metal and carbon dioxide. When 2.660 g2.660 \mathrm{~g} of magnetite is allowed to react with sufficient carbon monoxide, the CO2\mathrm{CO}_2 product is found to have a volume of 1.136 L1.136 \mathrm{~L} at 298 K298 \mathrm{~K} and 751 mmHg751 \mathrm{~mm} \mathrm{Hg} pressure.
(a) What mass of iron in grams is formed in the reaction?
(b) What is the formula of magnetite?
(c) Magnetite has a somewhat complicated cubic unit cell with an edge length of 839pm839 \mathrm{pm}. How many Fe and O\mathrm{O} atoms are present in each unit cell?

Solution

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We are given that magnetite reacts with carbon monoxide and produces iron metal and carbon dioxide.
Given data is:

density (magnetite)=5.20 g/cm3\text{density (magnetite)}= 5.20 \text{ g/cm}^3

m(magnetite)=2.660 gm\text{(magnetite)}= 2.660 \text{ g}

V(CO2)=1.136 LV(\mathrm{CO_2})= 1.136 \text{ L}

T=298 KT=298 \text{ K}

P=751 mm Hg/760 atm/mm Hg=0.988atmP= 751 \text{ mm Hg} / 760 \text{ atm/mm Hg}= 0.988 \text{atm}

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