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The molar enthalpy of vaporization of a liquid (ΔHvap )\left(\Delta H_{\text {vap }}\right) is the energy required to vaporize 1.00 mol1.00 \mathrm{~mol} of the liquid. In one experiment, 60.0 g60.0 \mathrm{~g} of liquid nitrogen (boiling point 196C-196^{\circ} \mathrm{C} ) is poured into a Styrofoam cup containing 2.00×102 g2.00 \times 10^2 \mathrm{~g} of water at 55.3C55.3^{\circ} \mathrm{C}. Calculate the molar enthalpy of vaporization of liquid nitrogen if the final temperature of the water is 41.0C41.0^{\circ} \mathrm{C}.

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Given:

Mass of liquid nitrogen=60g\mathrm{Mass \ of \ liquid \ nitrogen=60g}
Mass of water=2.0×102g\mathrm{Mass \ of \ water=2.0 \times10^2g}
Temperature(1)=55.3C\mathrm{Temperature(1)=55.3^\circ C}
Temperature(2)=41.0C\mathrm{Temperature(2)=41.0^\circ C}
ΔHvap of liquid nitrogen=?\mathrm{\Delta H_{vap } \ of \ liquid \ nitrogen=?}

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