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Question

The more aerodynamic a vehicle is, the less fuel the vehicle’s engine must use to overcome air resistance. To design vehicles that are as fuel efficient as possible, automotive engineers use the formula R =0.00256 ×DC×FA×s2\times D_C \times F_A \times s^2 where R is the air resistance (in pounds), DCD_C is the drag coefficient, FAF_A is the frontal area of the vehicle (in square feet), and s is the speed of the vehicle (in miles per hour). The formula assumes that there is no wind. Find the drag coefficient of a car when the air resistance is 50 pounds, the frontal area is 25 square feet, and the speed of the car is 45 miles per hour.

Solution

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Answered 1 year ago
Answered 1 year ago
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Substitute the given values of RR, FAF_A, and ss.

DC=500.0025625(45)2\begin{aligned} D_C = \frac{50}{0.00256 \cdot 25 \cdot (45)^2} \end{aligned}

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