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The National Ignition Facility has the most powerful laser in the world, using 192 lasers to aim 500 . TW of power at a spherical pellet of diameter 2.00 mm2.00 \mathrm{~mm}. How fast would a pellet of density 2.00 g/cm32.00 \mathrm{~g} / \mathrm{cm}^3 move if only a single laser hits it and 1.00%1.00 \% of the light is reflected?

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We will write expression for radiation force by which light beam from single laser acts on the spherical pellet. We will equate that expression with expression for force given by Second Newton's law. We will express and calculate acceleration of the spherical pellet from the obtained expression.

The given values are:

Pnet=500 TWP_{net}=500 \mathrm{~TW}

P=500 TW192=2.604 TWP=\dfrac{500 \mathrm{~TW}}{192}=2.604 \mathrm{~TW}

d=2 mmd=2 \mathrm{~mm}

ρ=2 gcm3\rho=2 \mathrm{~\dfrac{g}{cm^3}}

The surface of the pellet reflects only 1%1\% of the light, which means that the reflectance of the pellet is R=0.01R=0.01

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