## Related questions with answers

The owner of Bun ‘N’ Run Hamburgers wishes to compare the sales per day at two locations. The mean number sold for 10 randomly selected days at the Northside site was 83.55, and the standard deviation was 10.50. For a random sample of 12 days at the Southside location, the mean number sold was 78.80 and the standard deviation was 14.25. At the .05 significance level, is there a difference in the mean number of hamburgers sold at the two locations? What is the p-value?

Solution

VerifiedGiven:

$\begin{align*} n_1&=\text{Sample size}=10 \\ n_2&=\text{Sample size}=12 \\ \overline{x}_1&=\text{Sample mean}=83.55 \\ \overline{x}_2&=\text{Sample mean}=78.80 \\ s_1&=\text{Sample standard deviation}=10.50 \\ s_2&=\text{Sample standard deviation}=14.25 \\ \alpha&=\text{Significance level}=0.05 \end{align*}$

Given claim: The means differ

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis and the alternative hypothesis state the opposite of each other. The null hypothesis needs to include an equality.

$H_0:\mu_1=\mu_2$

$H_1: \mu_1 \neq \mu_2$

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