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The parasailing system shown uses a winch to let rope out at a constant rate so that the 70 kg70 \mathrm{~kg} rider moves away from the boat, which is traveling with a constant velocity. At the instant shown, the rope has a length of 30 m30 \mathrm{~m}, it is increasing in length at a constant 1 m/s1 \mathrm{~m} / \mathrm{s}, the angle is increasing at a rate of 0.05rad/s0.05 \mathrm{rad} / \mathrm{s}, and θ¨\ddot{\theta} is 0.01rad/s2-0.01 \mathrm{rad} / \mathrm{s}^2. Knowing that when the rope makes a 3030^{\circ} angle with respect to the water, the tension in the rope is 10kN10 \mathrm{kN}, determine the magnitude and direction of the force of the parasail on the parasailor.

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Knowns\textbf{Knowns}:

r=0.8 m

v0v_0=0

θ=30\theta=30^{\circ}

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