## Related questions with answers

The parasailing system shown uses a winch to let rope out at a constant rate so that the $70 \mathrm{~kg}$ rider moves away from the boat, which is traveling with a constant velocity. At the instant shown, the rope has a length of $30 \mathrm{~m}$, it is increasing in length at a constant $1 \mathrm{~m} / \mathrm{s}$, the angle is increasing at a rate of $0.05 \mathrm{rad} / \mathrm{s}$, and $\ddot{\theta}$ is $-0.01 \mathrm{rad} / \mathrm{s}^2$. Knowing that when the rope makes a $30^{\circ}$ angle with respect to the water, the tension in the rope is $10 \mathrm{kN}$, determine the magnitude and direction of the force of the parasail on the parasailor.

Solutions

Verified$\textbf{Knowns}$:

r=0.8 m

$v_0$=0

$\theta=30^{\circ}$

$\textbf{Given data}$

$\begin{align*} m_A&=20\text{ kg}\\ m_B&=25\text{ kg}\\ r&=0.8\text{ m}\\ \theta&=30\text{\textdegree} \end{align*}$

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