## Related questions with answers

The point of the needle of a sewing machine moves in SHM along the x -axis with a frequency of 2.5 Hz. At t = 0 its position and velocity components are +1.1 cm and -15 cm/s, respectively. Find the acceleration component of the needle at t = 0.

Solution

VerifiedHere given that the frequency of the needle of a sewing machine is $f = 2.5\,\mathrm{Hz}$.

At time $t = 0\,\mathrm{s}$, the position of the needle is $x_0 = + 1.1\,\mathrm{cm} = + 1.1\times10^{-2}\,\mathrm{m}$

and velocityof the needle is $v_{0\text{x}} = - 15\,\mathrm{cm\,s^{-1}} = - 15\times10^{-2}\,\mathrm{m\,s^{-1}}$. Here subscript $\text{x}$ shows that the motion is along x-axis.

$\textbf{(a)}$ As we know that the acceleration of the object in SHM is given by

$\begin{aligned} a_{\text{x}} = -\omega^2x\tag{1} \end{aligned}$

Here $\omega = 2\pi f$ and $x = x_0$, so

$\begin{aligned} a_{\text{x}} & = -4 \pi^2 f^2x_0\\ & = -4 \pi^2 \times \left(2.5\,\mathrm{Hz} \right)^2 \times 1.1\times10^{-2}\,\mathrm{m}\\ & = -4 \pi^2 \times \left(2.5\,\mathrm{s^{-1}} \right)^2 \times 1.1\times10^{-2}\,\mathrm{m}\\ & = -2.71\,\mathrm{m\,s^{-2}} \tag{2} \end{aligned}$

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