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Question

The points P(a,b,c)P(a, b, c) and Q(2,3,5)Q(2,3,5) are symmetric in the sense given. Find a,b,ca, b, c. About the plane z=4z=4.

Solution

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Answered 2 years ago
Answered 2 years ago
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The distance from point Q(2,3,5)Q(2,3,5) to the plane z=4z=4 is equal to the distance from point P(a,b,c)P(a,b,c) to the plane z=4z=4.

The value of that distance is 11.

Furthermore, the segment joining PP and QQ is perpendicular to the plane z=4z=4.

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