Question

The position of a particle as a function of time is given by (5 m/s)t+(3 m/s2)t2(-5\mathrm{~m} / \mathrm{s})t+ (3 \mathrm{~m} / \mathrm{s}^2)t^2. Plot xx verus tt for t=0t=0 to t=2st=2\mathrm{s}.

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The position of a particle as a function of time is given by

x=(5 ms)t+(3 ms2)t2x = \left(-5\mathrm{~\dfrac{m}{s}}\right )t + \left(3\mathrm{~\dfrac{m}{s^2}}\right )t^2

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