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Question

The position of a particle as a function of time is given by $(-5\mathrm{~m} / \mathrm{s})t+ (3 \mathrm{~m} / \mathrm{s}^2)t^2$. Plot $x$ verus $t$ for $t=0$ to $t=2\mathrm{s}$.

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VerifiedSolution A

Solution B

Answered 1 year ago

Step 1

1 of 2The position of a particle as a function of time is given by

$x = \left(-5\mathrm{~\dfrac{m}{s}}\right )t + \left(3\mathrm{~\dfrac{m}{s^2}}\right )t^2$

Step 1

1 of 2The graph of $x(t)=-5t+3t^2$ from t=0s to 2s.

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