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The rate constant for the decomposition of acetaldehyde, CH3CHO\mathrm{CH}_3 \mathrm{CHO}, to methane, CH4\mathrm{CH}_4, and carbon monoxide, CO\mathrm{CO}, in the gas phase is 1.1×102 L mol1 s11.1 \times 10^{-2} \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1} at 703 Kand 4.95 L mol1 s1703 \mathrm{~K}^{\text {and }} 4.95 \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1} at 865 K865 \mathrm{~K}. Determine the activation energy for this decomposition.

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Answered 2 years ago
Answered 2 years ago
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To calculate for the frequency factor of the reaction, we can use the Arrhenius equation:

k=AeEaRT\begin{aligned}k = Ae^{\frac{-E_{a}}{RT}}\end{aligned}

where kk stands for the rate constant, AA stands for the frequency factor, EaE_{a} stands for the activation energy, RR stands for the gas constant and TT stands for the temperature.

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