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Question

The rate constant for the second-order reaction

2NOBr(g)2NO(g)+Br2( g)2 \mathrm{NOBr}(\mathrm{g}) \longrightarrow 2 \mathrm{NO}(\mathrm{g})+\mathrm{Br}_2(\mathrm{~g})

is 0.80M1 s10.80 \mathrm{M}^{-1} \mathrm{~s}^{-1} at 10C10^{\circ} \mathrm{C}.
Starting with a concentration of 0.086M0.086 \mathrm{M}, calculate the concentration of NOBr\mathrm{NOBr} after 22 s.

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In this exercise, we need to calculate the concentration of NOBr after 22 seconds that the below-shown reaction has been ongoing:

2NOBr(g)2NO(g)+Br2(g)\mathrm{2NOBr(g)\rightarrow 2NO(g)+Br_2(g)}

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