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Question
The rate law for the reaction NH4^+ + NO2^- N2 + 2 H2O is given by rate = k[NH4^+ ][NO2^- ]. At 25 C, the rate constant is 3.0 × 10^-4 /M s. Calculate the rate of the reaction at this temperature if [NH4^+] = 0.26 M and [NO2^-] = 0.080 M.
Solution
VerifiedAnswered 4 months ago
Answered 4 months ago
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We have , [] = 0.26 , [] = 0.080 for the reaction
The rate law is given by
We need to find the reaction rate.
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