Question

# The reading on a metronome indicates the number of oscillations per minute. What are the frequency and period of the metronome's vibration when the metronome is set at 180?

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Given data: $n = 180$

In order to solve this problem we have to assume that, in the case of metronome, frequency is given as number of oscillations in one minute. Therefore we will have:

$f = \dfrac{n}{1\, \mathrm{min}}$

When we express it into seconds we get ($1\, \mathrm{min} = 60\, \mathrm{s}$):

$f = \dfrac{n}{60\, \mathrm{s}}$

And we can calculate period later as:

$T = \dfrac{1}{f}$

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