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The spin-orbit energy is proportional to SL\mathbf{S} \cdot \mathbf{L}. To evaluate SL\mathbf{S} \cdot \mathbf{L}, note that since J=S+L\mathbf{J}=\mathbf{S}+\mathbf{L},

J2=(S+L)(S+L)=S2+L2+2SLJ^2=(\mathbf{S}+\mathbf{L}) \cdot(\mathbf{S}+\mathbf{L})=S^2+L^2+2 \mathbf{S} \cdot \mathbf{L}

You can solve this for SL\mathbf{S} \cdot \mathbf{L} and then put in the values for J2,S2J^2, S^2, and L2L^2. [For instance, J2=j(j+1)2J^2=j(j+1) \hbar^2 where j=l±12j=l \pm \frac{1}{2}.] Show that if j=l+12j=l+\frac{1}{2} then SL=\mathbf{S} \cdot \mathbf{L}= l2/2l^2 / 2, and if j=l12j=l-\frac{1}{2}, then SL=(l+1)2/2\mathbf{S} \cdot \mathbf{L}=-(l+1) \hbar^2 / 2. Use these answers to prove that the spin-orbit splitting increases with increasing ll, as indicated in the above figure.

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The spin-orbit energy comes from the relative orientation of the orbital angular momentum L\bold{L} to the spin S\bold{S}. This energy is proportional to SL\bold{S}\cdot\bold{L} and causes a splitting of the orbital ll. The goal of this exercise is to find SL\bold{S}\cdot\bold{L}.

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