Try the fastest way to create flashcards
Question

The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standard deviation of s = 4.8 milligrams. Calculate a 95% two-sided confidence interval for σ.

Solution

Verified
Step 1
1 of 2

If s2s^2 is the sample variance from a random sample of nn observations from a normal distribution with unknown variance σ2\sigma^2, then a $\textbf{100(1α)%100(1 - \alpha)\% confidence interval for σ\sigma}$ is

(n1)s2χα2,n12σ(n1)s2χ1α2,n12\begin{align} \sqrt{\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}}}\leq\sigma\leq \sqrt{\frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}} \end{align}

where χα2,n12\chi^2_{\frac{\alpha}{2},n-1} and χ1α2,n12\chi^2_{1-\frac{\alpha}{2},n-1} are the upper and lower 100α2100\frac{\alpha}{2} percentage points of the chi-square distribution with n1n - 1 degrees of freedom, respectively.

We know that confidence level is 95%95\%, simple size n=10n= 10 and simple standard deviation s=4.8s=4.8, than

α2=10.952=0.025,and1α2=110.952=0.975.\begin{align*} \frac{\alpha}{2}=\frac{1-0.95}{2}=0.025,\quad \text{and}\quad 1-\frac{\alpha}{2}=1-\frac{1-0.95}{2}=0.975. \end{align*}

Therefore,

χα2,n12=χ0.025,92=19.02χ1α2,n12=χ0.975,92=2.70.\begin{align} \chi^2_{\frac{\alpha}{2},n-1}&=\chi^2_{0.025,9}=19.02\\ \chi^2_{1-\frac{\alpha}{2},n-1}&=\chi^2_{0.975,9}=2.70. \end{align}

Now, from Equations (1),(2) and (3) we get

9×4.8219.02σ9×4.822.70\sqrt{\frac{9\times 4.8^2}{19.02}}\leq\sigma\leq \sqrt{\frac{9\times 4.8^2}{2.70}}

Then, a 95%95\% two-sided confidence interval for σ\sigma is

3.3018σ8.7636\boxed{3.3018\leq\sigma\leq 8.7636}

Create a free account to view solutions

Create a free account to view solutions

Recommended textbook solutions

Probability and Statistics for Engineers and Scientists 9th Edition by Keying E. Ye, Raymond H. Myers, Ronald E. Walpole, Sharon L. Myers

Probability and Statistics for Engineers and Scientists

9th EditionISBN: 9780321629111 (4 more)Keying E. Ye, Raymond H. Myers, Ronald E. Walpole, Sharon L. Myers
1,204 solutions
Applied Statistics and Probability for Engineers 5th Edition by Douglas C. Montgomery, George C. Runger

Applied Statistics and Probability for Engineers

5th EditionISBN: 9780470053041Douglas C. Montgomery, George C. Runger
1,705 solutions
Probability and Statistics for Engineers and Scientists 4th Edition by Anthony J. Hayter

Probability and Statistics for Engineers and Scientists

4th EditionISBN: 9781111827045 (2 more)Anthony J. Hayter
1,341 solutions
Applied Statistics and Probability for Engineers 6th Edition by Douglas C. Montgomery, George C. Runger

Applied Statistics and Probability for Engineers

6th EditionISBN: 9781118539712 (1 more)Douglas C. Montgomery, George C. Runger
2,027 solutions

More related questions

1/4

1/7