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The surface of an iron component is to be hardened by carbon. The diffusion coefficient of carbon in iron at 1000C1000^\circ C is given to be 3×1011m2/s.3 \times 10^{–11} m^2/s. If the penetration depth of carbon in iron is desired to be 1.0 mm. the hardening process must take at least (a) 1.10 h (b) 1.47 h (c) 1.86 h (d) 2.50 h (e) 2.95 h

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Known:\textbf{Known:}

*  diffusion coefficient of carbon in iron $D_{AB}= 3 \cdot 10^{-11} \dfrac{\text{ m}^2}{\text{ s}}$
*  penetration depth of carbon in iron $\delta$= 1.0 mm= 0.001 m

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