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Question

The surface of an iron component is to be hardened by carbon. The diffusion coefficient of carbon in iron at $1000^\circ C$ is given to be $3 \times 10^{–11} m^2/s.$ If the penetration depth of carbon in iron is desired to be 1.0 mm. the hardening process must take at least (a) 1.10 h (b) 1.47 h (c) 1.86 h (d) 2.50 h (e) 2.95 h

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

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1 of 5$\textbf{Known:}$

```
* diffusion coefficient of carbon in iron $D_{AB}= 3 \cdot 10^{-11} \dfrac{\text{ m}^2}{\text{ s}}$
* penetration depth of carbon in iron $\delta$= 1.0 mm= 0.001 m
```

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