## Related questions with answers

The temperature coefficient of resistivity $\alpha$ is defined as the fractional increase of resistivity per degree Celsius, $\alpha=(1 / \rho) d \rho / d T$. According to the following table, what is the value of $\alpha$ for copper?

$\begin{aligned} &\begin{array}{lcc} \text { MATERIAL } & \rho & \alpha \\ \hline \text { Silver } & 1.6 \times 10^{-8} \Omega \cdot \mathrm{m} & 3.8 \times 10^{-3} /{ }^{\circ} \mathrm{C} \\ \text { Copper } & 1.7 \times 10^{-8} & 3.9 \times 10^{-3} \\ \text { Aluminum } & 2.8 \times 10^{-8} & 3.9 \times 10^{-3} \\ \text { Brass } & \approx 7 \times 10^{-8} & 2 \times 10^{-3} \\ \text { Nickel } & 7.8 \times 10^{-8} & 6 \times 10^{-3} \\ \text { Iron } & 10 \times 10^{-8} & 5 \times 10^{-3} \\ \text { Steel } & \approx 11 \times 10^{-8} & 4 \times 10^{-3} \\ \text { Constantan } & 49 \times 10^{-8} & 1 \times 10^{-5} \\ \text { Nichrome } & 100 \times 10^{-8} & 4 \times 10^{-4} \end{array}\\ &\text { At a temperature of } 20^{\circ} \mathrm{C} \text {. } \end{aligned}$

Solution

VerifiedWe have the definition for temperature coefficient $\alpha=\left(\dfrac{1}{\rho}\right)\dfrac{d\rho}{dT}$

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