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Question

The temperature of an incompressible substance of mass mm and specific heat cc is reduced from T0T_0 to T(<T0)T\left(<T_0\right) by a refrigeration cycle. The cycle receives energy by heat transfer at TT from the substance and discharges energy by heat transfer at T0T_0 to the surroundings. There are no other heat transfers. Plot (Wmin /mcT0)\left(W_{\text {min }} / m c T_0\right) versus T/T0T / T_0 ranging from 0.80.8 to 1.01.0, where WminW_{\min } is the minimum theoretical work input required.

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Answered 1 year ago
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Minimum work input is given by:

Wmin=mC(TT0)mCT0lnTT0W_{min}=m\cdot C\cdot (T-T_0)-m\cdot C\cdot T_0\cdot \ln{\dfrac{T}{T_0}}

We can now devide everything with mCT0m\cdot C\cdot T_0 and get the expression we need to plot the graph:

WminmCT0=TT01lnTT0\dfrac{W_{min}}{m\cdot C\cdot T_0}=\dfrac{T}{T_0}-1-\ln{\dfrac{T}{T_0}}

The task is to plot WminmCT0\dfrac{W_{min}}{m\cdot C\cdot T_0} versus TT0\dfrac{T}{T_0} ranging from 0.8 to 1.0, where WminW_{min} is the minimum theoretical work input required:

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