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The temperature of your skin is approximately $35.0^{\circ} \mathrm{C}$. c) Given your answer to part (b), why don't you glow as brightly as a light bulb? 36.24 A pure, defectfree, semiconductor material will absorb the electromagnetic radiation incident on it only if the energy of the individual photons in the incident beam is larger than a threshold value known as the bandgap of the semiconductor. Otherwise, the material will be transparent to the photons. The known roomtemperature bandgaps for germanium,
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$T = 35 \degree \mathrm{C} = 308.15 \ \mathrm{K} \rightarrow$ the temperature of a person's skin

$A = 2 \ \mathrm{m^2} \rightarrow$ total surface area of the skin

$\lambda_m = 9.41 \cdot 10^{6}\ \mathrm{m} \rightarrow$ the peak wavelength of the radiation of the skin (calculated in part (a) of the task)

$P = 1022.57\ \mathrm{W} \rightarrow$ the power of the radiation of the skin (calculated in part (b) of the task)

We are also assuming that one's skin radiates as a blackbody.
Our goal is to explain why aren't we glowing as a lightbulb given the power $P = 1022.57\ \mathrm{W}$ at which our skin is radiating.
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