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The temperature of your skin is approximately 35.0C35.0^{\circ} \mathrm{C}. c) Given your answer to part (b), why don't you glow as brightly as a light bulb? -36.24 A pure, defect-free, semiconductor material will absorb the electromagnetic radiation incident on it only if the energy of the individual photons in the incident beam is larger than a threshold value known as the band-gap of the semiconductor. Otherwise, the material will be transparent to the photons. The known room-temperature band-gaps for germanium,

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Given information:

  • T=35°C=308.15 KT = 35 \degree \mathrm{C} = 308.15 \ \mathrm{K} \rightarrow the temperature of a person's skin

  • A=2 m2A = 2 \ \mathrm{m^2} \rightarrow total surface area of the skin

  • λm=9.41106 m\lambda_m = 9.41 \cdot 10^{-6}\ \mathrm{m} \rightarrow the peak wavelength of the radiation of the skin (calculated in part (a) of the task)

  • P=1022.57 WP = 1022.57\ \mathrm{W} \rightarrow the power of the radiation of the skin (calculated in part (b) of the task)

  • We are also assuming that one's skin radiates as a blackbody.

Our goal is to explain why aren't we glowing as a lightbulb given the power P=1022.57 WP = 1022.57\ \mathrm{W} at which our skin is radiating.

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