Question

The thermal decomposition of phosphine (PH3)\left(\mathrm{PH}_3\right) into phosphorus and molecular hydrogen is a first-order reaction:

4PH3( g)P4( g)+6H2( g)4 \mathrm{PH}_3(\mathrm{~g}) \longrightarrow \mathrm{P}_4(\mathrm{~g})+6 \mathrm{H}_2(\mathrm{~g})

the time required for 95 percent of the phosphine to decompose..

Solution

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In this exercise, we need to calculate the time needed for 95% of phosphine to decompose into phosphorus and hydrogen.

The balanced chemical equation is as follows:

4PH3(g)P4(g)+H2(g)\mathrm{4PH_3(g)\rightarrow P_4(g) +H_2(g)}

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