Question

# The three blocks shown are identical. Blocks B and C are at rest when block B is hit by block A, which is moving with a velocity $v_A$ of 3 ft/s. After the impact, which is assumed to be perfectly plastic (e = 0), the velocity of blocks A and B decreases due to friction, while block C picks up speed, until all three blocks are moving with the same velocity v. Knowing that the coefficient of kinetic friction between all surfaces is $\mu_{k}=0.20$ , determine (a) the time required for the three blocks to reach the same velocity, (b) the total distance traveled by each block during that time.

Solution

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$\textbf{Knowns}$:

The three blocks shown are identical. Blocks B and C are at rest when block B is hit by block A, which is moving with a velocity $v_A$ of 3 ft/s.

After the impact, which is assumed to be perfectly plastic (e= 0),the velocity of blocks A and B decreases due to friction, while block C picks up speed, until all three blocks are moving with the same velocity v.

The coefficient of kinetic friction between all surfaces is $\mu_k$ = 0.20

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