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The TI-83/84 Plus calculator can be used to generate random data from a normally distributed population. The command randNorm(74, 12.5, 100) generates 100 values from a normally distributed population with μ=74\mu=74 and σ=12.5\sigma=12.5 (for pulse rates of women). One such generated sample of 100 values has a mean of 74.474.4 and a standard deviation of 11.7. Assume that σ\sigma is known to be 12.512.5 and use a 0.050.05 significance level to test the claim that the sample actually does come from a population with a mean equal to 74. Based on the results, does it appear that the calculator's random number generator is working correctly?

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H0:μ=74H_0:\mu=74

H1:μ74H_1:\mu\neq 74

Determine the value of the test-statistic:

z=xμσ/n=74.47412.5/1000.32z=\dfrac{\overline{x}-\mu}{\sigma /\sqrt{n}}=\dfrac{74.4-74}{12.5/\sqrt{100}}\approx 0.32

Determine the corresponding P-value in table A-2:

P=P(Z<0.32 or Z>0.32)=2×P(Z<0.32)=2×0.3745=0.7490P=P(Z<-0.32\text{ or }Z>0.32)=2\times P(Z<-0.32)=2\times 0.3745=0.7490

If the P-value is smaller than the significance level, reject the null hypothesis:

P>0.05 Fail to reject H0P>0.05\Rightarrow \text{ Fail to reject } H_0

There is not sufficient evidence to support the claim.

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