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The vacuum pressure of a condenser is given to be 80 kPa. If the atmospheric pressure is 98 kPa, what is the gage pressure and absolute pressure in kPa, kN/m2,lbf/in2,kN/m^2, lbf/in^2, psi, and mmHg.

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To calculate the gauge pressure\textbf{gauge pressure} pgp_g of a condenser we need to subtract the vacuum pressure\textbf{vacuum pressure} pv=80 kPap_v=80 \text{ kPa} from the atmospheric pressure\textbf{atmospheric pressure} patm=98 kPap_{atm}=98 \text{ kPa}:

pg=patmpvpg=98 kPa80 kPapg=18 kPa\begin{align*} p_g&=p_{atm}-p_v\\ p_g&=98 \text{ kPa}- 80\text{ kPa} \\ p_g&=\boxed{\color{#c34632}18 \text{ kPa} }\\ \end{align*}

The absolute pressure\textbf{absolute pressure} pp in this problem is the same as the vacuum pressure:

p=pv=80 kPa\begin{equation*} p=p_v=\boxed{\color{#c34632}80 \text{ kPa}}\\ \end{equation*}

To express the absolute pressure pp and the gauge pressure pgp_g in kNm2\text{kNm}^{-2}, lbfin2\text{lbfin}^{-2}, psi and mmHg we need to do some unit manipulation\textbf{unit manipulation}.

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