## Related questions with answers

Question

The value of $g$ at any latitude $\phi$ may be obtained from the formula

$g=32.09\left(1+0.0053 \sin ^2 \phi\right) \mathrm{ft} / \mathrm{s}^2$

which takes into account the effect of the rotation of the earth, as well as the fact that the earth is not truly spherical. Determine to four significant figures $(a)$ the weight in pounds, $(b)$ the mass in pounds, $(c)$ the mass in $\mathrm{lb} \cdot \mathrm{s}^2 / \mathrm{ft}$, at the latitudes of $0^{\circ}, 45^{\circ}, 60^{\circ}$, of a silver bar, the mass of which has been officially designated as $5\ \mathrm{lb}$.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 9**Given:**

- Value of g formula: $g= 32.09(1 + 0.0053 \sin^2f)\ \mathrm{ft/s^2}$;
- Mass of the silver bar: $m= 5\ \mathrm{lb}$;
- First latitude of the silver bar: $\alpha_1 = 0° \mathrm{}$;
- Second latitude of the silver bar: $\alpha_2 = 45° \mathrm{}$;
- Third latitude of the silver bar: $\alpha_3 = 60° \mathrm{}$;

**Required:**

a) Weight in pounds; b) Mass in pounds; c) Mass in $\mathrm{lbs^2/ft}$;

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