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Question

The value of gg at any latitude ϕ\phi may be obtained from the formula

g=32.09(1+0.0053sin2ϕ)ft/s2g=32.09\left(1+0.0053 \sin ^2 \phi\right) \mathrm{ft} / \mathrm{s}^2

which takes into account the effect of the rotation of the earth, as well as the fact that the earth is not truly spherical. Determine to four significant figures (a)(a) the weight in pounds, (b)(b) the mass in pounds, (c)(c) the mass in lbs2/ft\mathrm{lb} \cdot \mathrm{s}^2 / \mathrm{ft}, at the latitudes of 0,45,600^{\circ}, 45^{\circ}, 60^{\circ}, of a silver bar, the mass of which has been officially designated as 5 lb5\ \mathrm{lb}.

Solution

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Answered 1 year ago
Answered 1 year ago
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Given:

  • Value of g formula: g=32.09(1+0.0053sin2f) ft/s2g= 32.09(1 + 0.0053 \sin^2f)\ \mathrm{ft/s^2};
  • Mass of the silver bar: m=5 lbm= 5\ \mathrm{lb};
  • First latitude of the silver bar: α1=0°\alpha_1 = 0° \mathrm{};
  • Second latitude of the silver bar: α2=45°\alpha_2 = 45° \mathrm{};
  • Third latitude of the silver bar: α3=60°\alpha_3 = 60° \mathrm{};

Required:

a) Weight in pounds; b) Mass in pounds; c) Mass in lbs2/ft\mathrm{lbs^2/ft};

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