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Question

The vertices A, B, and C of a triangle in R3\mathbb{R}^{3} are given. Find the lengths of the sides of the triangle and determine whether it is a right triangle, an isosceles triangle, both, or neither.

A(1,1,1),B(3,3,2),C(3,3,5)A(1,1,1), B(3,3,2), C(3,-3,5)

Solution

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Answered 2 years ago
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The given vectors are A(1,1,1),B(3,3,2),C(3,3,5)A(1, 1, 1), B(3,3,2), C(3,-3,5). The component form of AB is

AB=(3,3,2)(1,1,1)=(2,2,1)\begin{gather} AB=(3,3,2)-(1, 1, 1)=(2,2,1) \end{gather}

Now the distance is

AB=22+22+12=4+4+1=9=3\begin{gather*} ||AB||=\sqrt{\left|{2}\right|^{2} + \left|{2}\right|^{2}+ \left|{1}\right|^{2}}=\sqrt{4+4+1} =\sqrt{9}=3 \end{gather*}

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