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Question

The volume of a gas at 99.0 KPa is 300.0 mL. If the pressure is increased to 188 KPa, what will be the new volume?

Solution

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Answered 1 year ago
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As per Boyle's law, for a given amount of gas held at a constant temperature, the product of pressure and volume is constant\

P1V1=P2V2P_1V_1 = P_2V_2

where P1_1 and V1_1 represent the initial conditions, and P2_2 and V2_2 represent new conditions.

Given P1_1 = 99.0 kPa\mathrm{kPa}, P2_2 = 188 kPa\mathrm{kPa} and V1_1 = 300 mL\mathrm{mL}, we can calculate:

V2=P1V1P2=300×99188=158mLV_2 = \dfrac{\text{P$_1$V$_1$}}{\text{P$_2$}} = \dfrac{300 \times 99}{188} = 158 \mathrm{mL}

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