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# The volume of a gas at 99.0 KPa is 300.0 mL. If the pressure is increased to 188 KPa, what will be the new volume?

Solution

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As per Boyle's law, for a given amount of gas held at a constant temperature, the product of pressure and volume is constant\

$P_1V_1 = P_2V_2$

where P$_1$ and V$_1$ represent the initial conditions, and P$_2$ and V$_2$ represent new conditions.

Given P$_1$ = 99.0 $\mathrm{kPa}$, P$_2$ = 188 $\mathrm{kPa}$ and V$_1$ = 300 $\mathrm{mL}$, we can calculate:

$V_2 = \dfrac{\text{P_1V_1}}{\text{P_2}} = \dfrac{300 \times 99}{188} = 158 \mathrm{mL}$

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