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Question

The wheels of a midsize car exert a force of 2100 N backward on the road to accelerate the car in the forward direction. If the force of friction including air resistance is 250 N and the acceleration of the car is $1.80\ \mathrm{m} / \mathrm{s}^{2},$ what is the mass of the car plus its occupants? Explicitly show how you follow the steps in the Problem-Solving Strategy for Newton's laws of motion. For this situation, draw a free-body diagram and write the net force equation.

Solution

VerifiedAnswered 5 months ago

Answered 5 months ago

Step 1

1 of 2Writing the Newton's second law:

$F_{tot} = ma = F_{car} - F_{drag}$

Solving for $m$:

$m = \frac{ F_{car} - F_{drag} }{ a } = \frac{ 2100 \text{ N} - 250 \text{ N} }{ 1.80 \text{ m/s}^2 } = \boxed{ 1027.78 \text{ kg} }$

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