## Related questions with answers

Three point charges lie along a straight line, where $q_{1}=6.00 \mu \mathrm{C},$ $q_{2}=1.50 \mu \mathrm{C},$ and $q_{3}=-2.00 \mu \mathrm{C}$. The separation distances are $d_{1}=3.00 \mathrm{cm}$ and $d_{2}=2.00 \mathrm{cm}$. Calculate the magnitude and direction of the net electric force on (a) $q_{1},$ (b) $q_{2}$, and (c) $q_{3}$.

Solution

Verified### 1 Concepts and Principles

$\textbf{Coulomb's Law}$: the electrostatic force exerted by a point charge $\textcolor{#c34632}{q_1}$ on a second point charge $\textcolor{#c34632}{q_2}$ separated by a distance $\textcolor{#c34632}{r}$ is directly proportional to the product of the two charges and is inversely proportional to the square of the distance between them:

$\begin{equation*} F_{12}=k_e\dfrac{q_1q_2}{r^2}\overrightarrow{\mathbf{r}}_{12}\tag{*} \end{equation*}$

where $\textcolor{#c34632}{k_e=8.988\times 10^9\;\mathrm{N\cdot m^2/C^2}}$ is Coulomb constant and $\textcolor{#c34632}{\overrightarrow{\mathbf{r}}_{12}}$ is a unit vector directed from $\textcolor{#c34632}{q_1}$ toward $\textcolor{#c34632}{q_2}$.

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