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Question

To be rescued from the roof of a burning building, a 70-kg man must be able to jump straight up and catch hold of a rope ladder hanging from a helicopter. He has to raise his center of mass 2.00 m above the roof to do so. (a) If he crouches down such that his center of mass is 0.50 m above the roof and his feet leave the roof when his center of mass is 1.05 m above the roof, what minimum force must he exert on the roof to reach the ladder? (b) A typical candy bar contains about 850 kJ of food energy. How many candy bars does this jump require?

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 6**Given data:**

mass of the man $m$ = $70\ \text{kg}$

displacement of his center of mass $d_{ladder}$ = $2.00\ \text{m}$

gravity $g$ = $9.81\ \text{m/s}^2$

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