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To be rescued from the roof of a burning building, a 70-kg man must be able to jump straight up and catch hold of a rope ladder hanging from a helicopter. He has to raise his center of mass 2.00 m above the roof to do so. (a) If he crouches down such that his center of mass is 0.50 m above the roof and his feet leave the roof when his center of mass is 1.05 m above the roof, what minimum force must he exert on the roof to reach the ladder? (b) A typical candy bar contains about 850 kJ of food energy. How many candy bars does this jump require?

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Answered 2 years ago
Answered 2 years ago
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Given data:

mass of the man mm = 70 kg70\ \text{kg}

displacement of his center of mass dladderd_{ladder} = 2.00 m2.00\ \text{m}

gravity gg = 9.81 m/s29.81\ \text{m/s}^2

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