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To escape Earth’s gravitational field, a rocket must be launched with an initial velocity called the escape velocity.A rocket launched from the surface of Earth has velocity (in miles per second) given by v = √2GM/r + v_0^2 - 2GM/R ≈ √192000/r + v_0^2 - 48 where v_0 is the initial velocity, r is the distance from the rocket to the center of Earth, G is the gravitational constant, M is the mass of Earth, and R is the radius of Earth (approximately 4000 miles). (b) A rocket launched from the surface of the moon has velocity v (in miles per second) given by v = √1920/r + v_0^2 - 2.17. Find the escape velocity for the moon.

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Again we set r,v0r\to \infty, v\to 0. Putting them in the equation we get 0+v022.170v0=2.170+v_0^2-2.17\to 0\Rightarrow v_0=\sqrt{2.17}

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