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To get off a frozen, frictionless lake, a 65.0 kg65.0\ \mathrm{kg} person takes off a 0.150 kg0.150\ \mathrm{kg} shoe and throws it horizontally, directly away from the shore with a speed of 2.00 m/s2.00\ \mathrm{m/ s}. If the person is 5.00 m5.00\ \mathrm{m} from the shore, how long does he take to reach it?

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Answered 2 years ago
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To get off a frozen lake, the person of mass:

M=65 kgM=65\text{ kg}

takes off a shoe of mass

m=0.150 kgm=0.150\text{ kg}

and throws it horizontally, directly away from the shore with speed

u=2.0 m/su=2.0\text{ m/s}

Let us consider the person got a speed vv after throwing his shoe.

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