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Question

ABCDEF,EF=x27\triangle A B C \cong \triangle D E F, E F=x^2-7, and BC=4x - 2. Find the values of x.

(A) -1 and 5

(B) -1 and 6

(C) 1 and 5

(D) 2 and 3

Solution

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Step 1
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Given that ABCDEF\triangle ABC\cong\triangle DEF, then BCEF\overline{BC}\cong \overline{EF} by CPCTC:

BC=EFBC=EF

4x2=x274x-2=x^2-7

0=x24x50=x^2-4x-5

Factor the right side:

0=(x+1)(x5)0=(x+1)(x-5)

By zero product property,

x=1,5(1)x=-1,5\color{white}\tag{1}

So, the correct answer is choice A.\textbf{\color{#c34632}A.}

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